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As businesses continue to realize how expensive and time-consuming it is to move people around the country for meetings, and as the VR technology gets better and better, eventually there will be this mass realization that virtual presence called telepresence in the jargon is good enough, and perhaps better, if you factor in travel costs and time away from work Add the further enhancement of desktop video, and the future is here The delivery mechanism for all these visually oriented systems is equally complex and exciting One area that is as yet undefined is the whole question of who the network players will be and telephone companies, cable providers, and application designers are all jockeying for position Already alliances are emerging that will help determine the shape of the interactive, entertainment-oriented future And what about the non-entertainment market Indeed, applications are out there, built around images, video, and virtual reality.

Suppose we have a series circuit with a supply of 150 V and three resistors: R1 330 , R2 680 , and R3 910 . What is the power dissipated by R2 You must find the current in the circuit. To do this, calculate the total resistance first. Because the resistors are in series, the total is R 330 680 910 1920 . Then the current is I 150/1920 0. 07813 A 78.1 mA. The power in R2 is P2 I 2R2 0.07813 0.07813 680 4.151 W. Round this off to two significant digits, because that s all we have in the data, to obtain 4.2 W. The total power dissipated in a series circuit is equal to the sum of the wattages dissipated in each resistor. In this way, the distribution of power in a series circuit is like the distribution of the voltage.

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The current in a series circuit is the same at every point along the way. The voltage across any resistance in a parallel combination of resistances is the same as the voltage across any other resistance, or across the whole set of resistances. The voltages across resistances in a series circuit always add up to the supply voltage. The currents through resistances in a parallel circuit always add up to the total current drawn from the supply. The total wattage consumed in a series or parallel circuit is always equal to the sum of the wattages dissipated in each of the resistances. Now, let s get acquainted with two of the most famous laws that govern dc circuits. These rules are broad and sweeping, and they make it possible to analyze complicated series-parallel dc networks.

Medicine.

Problem 5-8

The physicist Gustav Robert Kirchhoff (1824 1887) was a researcher and experimentalist in a time when little was understood about how electric currents flow. Nevertheless, he used certain commonsense notions to deduce two important properties of dc circuits.

Calculate the total power in the circuit of Problem 5-7 by two different methods. The first method is to figure out the power dissipated by each of the three resistors separately, and then add the figures up. The power P2 is already known. Let s bring it back to the four significant digits while we calculate: P2 4.151 W. Recall that the current in the circuit is I 0.07813 A. Then P1 0.07813 0. 07813 330 2.014 W, and P3 0.07813 0.07813 910 5.555 W. Adding these gives P 2.014 4.151 5.555 11.720 W. Round this off to 12 W. The second method is to find the series resistance of all three resistors. This is R 1920 , as found in Problem 5-7. Then P I 2R 0.07813 0.07813 1920 11.72 W, again rounded to 12 W. You might recognize this as an electrical analog of the distributive law you learned in junior-high-school algebra.

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