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class Exc1 { static void subroutine() { int d = 0; int a = 10 / d; } public static void main(String args[]) { Exc1subroutine(); } } The resulting stack trace from the default exception handler shows how the entire call stack is displayed: javalangArithmeticException: / by zero at Exc1subroutine(Exc1java:4) at Exc1main(Exc1java:7) As you can see, the bottom of the stack is main's line 7, which is the call to subroutine( ), which caused the exception at line 4 The call stack is quite useful for debugging, because it pinpoints the precise sequence of steps that led to the error

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The first two terms on the right side of each equation express a difference having the form, Mxi Mi These quantities are proper9 changes of mixing, symbol A M By definition,

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Although the default exception handler provided by the Java run-time system is useful for debugging, you will usually want to handle an exception yourself Doing so provides two benefits First, it allows you to fix the error Second, it prevents the program from automatically terminating Most users would be confused (to say the least) if your program stopped running and printed a stack trace whenever an error occurred! Fortunately, it is quite easy to prevent this To guard against and handle a run-time error, simply enclose the code that you want to monitor inside a try block Immediately following the try block, include a catch clause that specifies the exception type that you wish to catch To illustrate how easily this can be done, the following program includes a try block and a catch clause which processes the ArithmeticException generated by the division-by-zero error: class Exc2 { public static void main(String args[]) { int d, a; try { // monitor a block of code d = 0; a = 42 / d; Systemoutprintln("This will not be printed"); } catch (ArithmeticException e) { // catch divide-by-zero error Systemoutprintln("Division by zero"); } Systemoutprintln("After catch statement"); } } This program generates the following output: Division by zero After catch statement Notice that the call to println( ) inside the try block is never executed Once an exception is thrown, program control transfers out of the try block into the catch block Put differently, catch is not "called," so execution never "returns" to the try block from a catch Thus, the line "This will not be printed" is not displayed Once the catch

where M is a molar (or unit-mass) solution property and M iis a molar (or unit-mass) purespecies property, all at the same T and P Now Eqs (1225) through (1228) can be written:

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where AG, A S , A V , and AH are the Gibbs energy change of mixing, the entropy change of mixing, the volume change of mixing, and the enthalpy change of mixing For an ideal solution, each excess property is zero, and for this special case Eqs (1230) through (1233) become:

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