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// This program averages a list of numbers entered by the user using System; using SystemIO; class AvgNums { static void Main() { string str; int n; double sum = 00; double avg, t; ConsoleWrite("How many numbers will you enter: "); str = ConsoleReadLine(); try { n = Int32Parse(str); Convert a string to an int } catch(FormatException exc) { ConsoleWriteLine(excMessage); return; } catch(OverflowException exc) { ConsoleWriteLine(excMessage); return; } ConsoleWriteLine("Enter " + n + " values"); for(int i=0; i < n ; i++) { ConsoleWrite(": "); str = ConsoleReadLine(); try { t = DoubleParse(str); Convert a string to a double } catch(FormatException exc) { ConsoleWriteLine(excMessage); t = 00; } catch(OverflowException exc) { ConsoleWriteLine(excMessage); t = 0; } sum += t;

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// Make the new set one element larger than the original Set newset = new Set(obLength+1); // Copy elements into the new set for(int i=0; i < obLength; i++) newsetmembers[i] = obmembers[i]; // Set the Length property newsetLength = obLength+1; // Add new element to new set newsetmembers[newsetLength-1] = ch; return newset; // return the new set } }

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Notice how the ThreeD objects are used to control if statements and a while loop In the case of the if statements, the ThreeD object is evaluated using true If the result of this operation is true, then the if statement succeeds In the case of the do-while loop, each iteration of the loop decrements b The loop repeats as long as b evaluates as true (that is, it contains at least one non-zero coordinate) When b contains all zero coordinates, it evaluates as false when the true operator is applied and the loop stops

As you know, C# defines the following logical operators: &, |, !, &&, and || Of these, only the &, |, and ! can be overloaded By following certain rules, however, the benefits of the short-circuit && and || can still be obtained Each situation is examined here

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This method bears some close examination First, the find( ) method is called to determine if ch is already part of the set If it returns anything other than 1, ch is already in the set, so a copy of the original set is returned Otherwise, a new set called newset is created that will hold the contents of the original set referred to by ob, plus the new element, ch Notice that it is created one element larger than ob to accommodate the new element Next, the original elements are copied into newset, and the length of newset is set to one greater than the original set Next, ch is added to the end of newset Finally, newset is returned In all cases, the original set is untouched by this operation and a new set is returned Thus, the returned set is separate and distinct from the set passed as an operand

Let s begin with the simplest situation If you will not be making use of the short-circuit logical operators, then you can overload & and | as you would intuitively think, with each returning a bool result An overloaded ! will also usually return a bool result Here is an example that overloads the !, &, and | logical operators for objects of type ThreeD As before, each assumes that a ThreeD object is true if at least one coordinate is non-zero If all three coordinates are zero, then the object is false

// A simple way to overload !, |, and & for ThreeD using System; // A three-dimensional coordinate class class ThreeD { int x, y, z; // 3-D coordinates public ThreeD() { x = y = z = 0; } public ThreeD(int i, int j, int k) { x = i; y = j; z = k; }

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7 Next, overload so that it removes an element from the set, as shown here: // Remove an element from the set public static Set operator -(Set ob, char ch) { Set newset = new Set(); int i = obfind(ch); // i will be -1 if element not found // Copy and compress the remaining elements for(int j=0; j < obLength; j++) if(j != i) newset = newset + obmembers[j]; return newset; }