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the Ohio population does not deviate from HardyWeinberg proportions at the MN locus Earlier (chapter 4), we used the chi-square statistic to test how well real data t an expected data set based on a ratio predicted before the test For example, we tested the data against a 3:1 ratio in table 42 In that case, the number of degrees of freedom was simply the number of independent categories: the total number of categories minus one Here, however, our expected ratio is derived from the data set itself The values p2, 2pq, and q2 came from p and q, which were estimated from the data In this case, we lose one additional degree of freedom for every independent value we estimate from the data If we calculate p from a sample, we lose one degree of freedom.

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Analysis: First, we de ne the phasors and impedances at the frequency of interest in the problem, = 377 rad/s: Z = R + j L = 4 + j 3 = 5 (0644) V = 10 2 10 V 2 = 2 ( 2215) = I= Z 5 (0644)

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However, we do not lose a degree of freedom for estimating q, since q is no longer an independent variable: q 1 p So in the previous case, we lose two degrees of freedom one for estimating p and one for independent categories The general rule of thumb in using chisquare analysis to test for data t to Hardy-Weinberg proportions is that the number of degrees of freedom must equal the number of phenotypes minus the number of alleles (in this case, 3 2 1) The chi-square analysis in table 192 may seem paradoxical Because the observed allelic frequencies calculated from the original genotypic data are used to calculate the expected genotypic frequencies, it may appear to some individuals that the analysis must, by its very nature, show that the population is in HardyWeinberg proportions.

The average power can be computed from the phasor quantities: Pav = VI cos( ) = 10 2 cos(0644) = 16 W The instantaneous power is given by the expression: p(t) = v(t) i(t) = 2 10 sin(377t) 2 2 cos(377t 2215) W The instantaneous voltage and current waveforms and the instantaneous and average power are plotted in Figure 76

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It can be further seen that it is impossible to design a bearing at Kg = 04 for the available machining capability Figure 746 (b) can be used to determine the number of jets per row d is the minimum possible hole diameter (0005 in), whereas d* (00032 in) is the value calculated previously for Kg = 04 The number of jets per row (ie 3) is read from the horizontal axis from the intersection of (d/d* =16) and the curve Figure 748 shows that the three jets are not sufficient as these are not included in the curves A better design would be to use either six or eight feed holes per row of either a 50 10 3 in or 60 10 3 in diameter with both alternatives providing a gauge pressure ratio of between 06 and 08, since the ratio of d/d* is equal or less than 1 at the corresponding Kg values

Voltage and current waveforms for Example 71 20 10 0 10 20 0 0005 001 0015 t (s) 002 0025 003 0035

To demonstrate that this is not necessarily the case, a counterexample appears in table 193 We use data similar to the Ohio sample, except that the original number of heterozygotes has been distributed equally among the two homozygote classes The same allelic frequencies are maintained, yet the genotypic distribution differs The chi-square value of 20000 for these data demonstrates that the population represented in table 193 is not in Hardy-Weinberg proportions Thus, a chi-square analysis of t to the HardyWeinberg proportions by no means represents circular reasoning..

v(t) i(t) ) Volts ( ), amps (

Instantaneous and average power for Example 71 40 30 p(t)

MN 76 2pq (0.3648) 72.96 0.127

important to remember that we have de ned phasors to have rms amplitude in power calculation This is a standard procedure in electrical engineering practice Note that the instantaneous power can be negative for brief periods of time, even though the average power is positive

Fig 748: Influence of the number of jets on the load coefficient [3]

114 p2 (0.5776) 115.52 0.020

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