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he last step in your journey through Ajax- and PHP-based web application development revolves around the DOM. The DOM is a representation of all the objects and elements on a web page. Using a tree structure, all paragraphs, images, links, and other elements can be directly accessed and manipulated using JavaScript. One of the key aspects of developing Ajax-based applications is the manipulation of elements on an HTML page using the DOM. In numerous examples in previous chapters, we have updated the innerHTML property of a given div. This is an example of updating an element s property via the DOM. This is one of the most basic things you can do using the DOM; there are, of course, more advanced effects you can achieve, such as dynamically creating new elements for the HTML page, and removing events. The DOM also allows you to dynamically update the CSS styles of a given element. While debugging JavaScript can be tricky enough when working with Ajax-based server-side requests, working with the DOM can be even more intimidating. To become an adept DOM wrangler, you must understand how elements relate to each other, what sorts of attributes and methods are available to use, and how to go about accessing what is on the page. Throughout this chapter, we will go into basic examples on how to use the DOM to your advantage and open the door to more advanced techniques.

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class ListNode { friend class List<T>; friend class ListItercT>;

public: ListNode(T& protected: t, ListNodecT>* p) : data(t), next(p) { }

make_heap(p,q); // rearranges the elements of [p,q[ into a heap; // postcondition: [p,q[ is a heap;

T data;

int main() { int a[] = {44,88,33,77,11,99,66,22,55}; print(a,9); make_heap(a,a+9); print(a,9); } n=9: {44,88,33,77,11,99,66,22,55} n=9: {99,88,66,77,11,33,44,22,55} 77 max(x,y); // returns the maximum of x and y; 22 55

ListNode* next;

An iterator acts like a window, allowing access to one item at a time in the container. Iterators are sometimes called cursors because they locate a specific element among the entire structure, the same way that a cursor on your computer screen locates one character location. A structure may have more than one iterator. For example, one could declare three iterators on a list like this:

99 88 11 33 66 44

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Before you get started manipulating elements in the DOM, you need to know the various methods for accessing different elements. There are many ways to achieve this, so here we will just look at the most common methods.

List<float> list; ListItercfloat> itl(list), it2(list), it3(list); itl.insert(ll.01); 'itl++; itl.insert(22.02); itl++; itl.insert(33.03); for (it2.resetO; !it2; 1U++) it2 = lO*it2; // multiplies each stored number by 10 it3 = itl; // replaces 110.1 with 330.3 in first item

int main() { cout << "max(48,84)=" << max(48,84) << '\n'; } max(48,84)=84

The iterators are independent of each other. While i t2 traverses the list, i t 1 remains fixed on the third item.

13.1 13.2 13.3 13.4

max_element(p,q); // returns the position of the maximum element in the segment [pp,qq[; // invariant: [p,q[ is left unchanged;

What is the difference between a function template and a template function What is the difference between a class template and a template class

int main() { int a[] = {77,22,99,55,11,88,44,33,66}; const int* p = max_element(a,a+9); cout << "*p=" << *p << '\n'; cout << "p-a=" << p-a << '\n'; } *p=99 p-a=2

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A minimum function should compare two objects of the same type and return the object whose value is smaller. The type should be the template parameter T: template <class T> T min(T x, T y) return ( x < y x : y );

This is probably one of the functions that you will use the most. If you want to access a specific element (be it a div, a link, or an image), you can simply assign it an ID, and then pass that ID to this method.

This implementation uses the conditional expression operator: (x<y x: than y, the expression evaluates to x; otherwise it evaluates to y.

merge(p,q,pp,qq,ppp); // merges the segments [p,q[ and [pp,qq[ into [ppp,ppp+n[, // where n = q - p + qq - pp; // precondition: [p,q[ and [pp,qq[ must be sorted; // postcondition: the segment [ppp,ppp+n[ is sorted; // invariant: [p,q[ and [pp,qq[ are left unchanged;

Here is the test driver and a sample run: #include #include main0 tout << "min(22, 44) = ' -CC min(22, 44) << endl; tout << "min(66.66, 33.33) = ' -CC min(66.66, 33.33) C-C endl; Rational x(22, 7), ~(314, 100); tout << "min(x, y) = ' << min(x, y) << endl; min(22, 4 4 ) = 2 2 minfcSf5.66, 33,33) = 3 3 . 3 3 mink, y) ;f 324/100 13.6 , <iostream.h> "Rationa1.h"

int main() { int a[] = {22,55,66,88}; int b[] = {11,33,44,77,99}; int c[9]; merge(a,a+4,b,b+5,c); print(c,9); } n=9: {11,22,33,44,55,66,77,88,99}