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[Solved] pdf editing API for Asp . Net and Vb - CodeProject
this may help you. Pdf Api for editing on Asp , net [^] PDF API for .NET [^].

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rotate_copy(p,r,q,pp); // copies the segment [r,q[ into [pp,pp+m[, where m = q-r, // and copies the segment [p,r[ into [pp+m,pp+n[, where n = q-p; // returns pp+m+n; // invariant: [p,q[ remains unchanged;

1.10 a. 37/ (5*2) evaluatesto 37/10 b. 37/5/2 e v a l u a t e s t o (37/5)

/2 = 7/2 = 3

int main() { char* s="ABCDEFGHIJKLMNOPQRSTUVWXYZ"; cout << s << '\n'; char buffer[80]; char* ss = rotate_copy(s,s+4,s+26,buffer); *ss = 0; // truncate buffer for printing cout << s << '\n'; cout << buffer << '\n'; } ABCDEFGHIJKLMNOPQRSTUVWXYZ ABCDEFGHIJKLMNOPQRSTUVWXYZ EFGHIJKLMNOPQRSTUVWXYZABCD

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Editing PDF document online and save in the database using ASP . NET ...
This is the difficult part of your question: Now, I want to allow the users to edit the data in the PDF file shown inside the iFrame and also ...

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c. This is not valid because there is no operator between 3 7 a n d ( 5 / 2 ) . T h e intended operation was 3 7 * ( 5 / 2 ) , which evaluates to 3 7 / 2 = 18 d. 37%(5%2) e. 37%5%2 evaluatesto 37%1 = 0 2%2 = 0

search(p,q,pp,qq); // searches for the subsequence [pp,qq[ in [p,q[; // if found, the position r of its first occurrence is returned; // otherwise, q is returned; // postcondition: either r = q or [r,r+n[ = [pp,qq[, where n = qq-pp; // invariant: [p,q[ is left unchanged;

evaluatesto (37%5)%2 =

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//functions.js function checkfortasks (thedate, e){ theObject = document.getElementById("taskbox"); theObject.style.visibility = "visible"; var posx = 0; var posy = 0; posx = e.clientX + document.body.scrollLeft; posy = e.clientY + document.body.scrollTop; theObject.style.left = posx + "px"; theObject.style.top = posy + "px"; serverPage = "taskchecker.php thedate=" + thedate; objID = "taskbox"; var obj = document.getElementById(objID); xmlhttp.open("GET", serverPage); xmlhttp.onreadystatechange = function() { if (xmlhttp.readyState == 4 && xmlhttp.status == 200) { obj.innerHTML = xmlhttp.responseText; } } xmlhttp.send(null); } function hidetask (){ tObject = document.getElementById("taskbox"); tObject.style.visibility = "hidden"; tObject.style.height = "0px"; tObject.style.width = "0px"; }

$ 37 - 5 - 2 evaluatesto (37 - 5) - 2 = 32 - 2 = 30 g. This is not valid because there is no operator between ( 3 7 - 5 > a n d 2. T h e intended operation was ( 3 7 - 5 ) * 2, which evaluates to 3 2 * 2 = 6 4

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int main() { char* p="ABCDEFGHIJKLABCDEFGHIJKL"; char* pp="HIJK"; char* r = search(p,p+24,pp,pp+4); int n = r-p; // number of characters before pp in p cout << "n=r-p=" << n << '\n'; cout << "*r=" << *r << '\n'; cout << p << '\n'; cout << string(n,'-') << pp << string(20-n,'-') << '\n'; pp = "LMNOp"; r = search(p,p+24,pp,pp+5); n = r-p; cout << "n=r-p=" << n << '\n'; cout << p << '\n'; cout << string(n,'-') << '\n'; } n=r-p=7 *r=H ABCDEFGHIJKLABCDEFGHIJKL -------HIJK------------n=r-p=24 ABCDEFGHIJKLABCDEFGHIJKL ------------------------

1.11 a. m - 8 - n evaluates to ( 2 4 -8)-7=16-7=9 b. m = n = 3 evaluates to 3 c. m%n evaluates to 2 4 %7 = 3 d. m%n++ evaluates to 24% (7++) = 24%7 = 3 e. m%++n evaluates to 24% (++7) = 24%8 = 0 f. ++m - n-evaluatesto (++24) - (7--) = 25 - 7 = 8

APP. E]

g. m += n -= 2 evaluatesto += (7 -= 2) = 24 += 5 = 29 1.12 a. r2 d2 is a valid identifier b. H20 is a valid identifier C. d. secondCousinOnceRemoved 2ndBir thday isavalididentifier

g. - 12 3 4 5 is a valid identifier h. x ( 3 ) is not a valid identifier because it contains the characters ( and ) i. cos t-in-$ is not a valid identifier because it contains the character $

search_n(p,q,n,x); // searches for the subsequence of n consecutive copies of x in [p,q[; // if found, the position r of its first occurrence is returned; // otherwise, q is returned; // postcondition: either r = q or [r,r+n[ = [pp,qq[, where n = qq-pp; // invariant: [p,q[ is left unchanged;

<div id="myDiv" onclick="removeElement(this)"> Click me to to remove me! </div> <script type="text/javascript"> function removeElement(elt) { elt.parentNode.removeChild(elt); } </script>

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