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where i t is an iterator. The expression ( ! i t ) is read a current item exists, because the function will return 1 (i.e., true ) if current is not NULL. We use this function to check the status of the current pointer before invoking an insertion or deletion function that requires using the pointer.

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The operator++0 increments the iterator by advancing its current pointer to the next item in the list after advancing its previous pointer. It precedes this action with the same resetting procedure that the operator ! ( ) function performed if it finds the current pointer NULL:

generate_n(p,n,f); // assigns the outputs of successive calls f(x) to each x in [p,p+n[;

int ListIter<Tx:operator++()

long fibonacci(); int main() { int a[10]={0}; generate_n(a,10,fibonacci); print(a,10); } long fibonacci() { static int f1=0, f2=1; int f0=f1; f1 = f2; f2 += f0; return f0; } n=10: {0,1,1,2,3,5,8,13,21,34}

// reset current pointer if (current == NULL) == NULL) current = list.first; if (previous else current = previous->next; // advance current pointer else { previous = current; current = current->next; return (current != NULL); // returns TRUE if current exists

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Figure 13-8. Fiddler displays all the information about requested files when a web page is loaded in Internet Explorer.

This operator allows for easy traversal of the list:

includes(p,q,pp,qq); // returns true iff every element of [pp,qq[ is found in [p,q[; // precondition: both segments must be sorted; // invariant: [p,q[ and [pp,qq[ are left unchanged;

for (it.reset(); !it; it++) . . .

int main() { int a[] = {0,1,1,2,3,5,8,13,21,34}; int b[] = {0,1,2,3,4}; bool found = includes(a,a+10,b,b+5); cout << "found=" << found << '\n'; found = includes(a,a+10,b,b+4); cout << "found=" << found << '\n'; } found=0 found=1

just like an ordinary for loop traversing an array. It resets the iterator to locate the first item in the list. Then after visiting that item, it increments the iterator to advance and visit the next item. The loop continues as long as ! it returns true , which means that there is still an item to be visited. The ins er t ( t > function creates a new node for t and then inserts that node immediately after the current node:

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template<class T> void ListIter<T>::insert(T t) { ListNode<T>* p = list.newNode(t,O); if (list.isEmpty()) list-first = p; else { p->next = current->next; current->next = p;

inner_product(p,q,pp,x) // returns the sum of x and the inner product of [p,q[ with [pp,pp+n[, // where n = q-p; // invariant: [p,q[ and [pp,qq[ are left unchanged;

The insert operation can be visualized like this:

When you request the Fiddler web site in Internet Explorer, all files involved in requesting the page are listed. There are a wide range of options available to view, mostly on the Session Inspector tab. On this tab, you can view request and response headers, returned data (if the file is an image, you can view it), and submitted form data. You can also manually build your own HTTP requests to execute. On the whole, this is a very powerful and useful tool, but by default it will only work for Internet Explorer. Fiddler acts as an HTTP proxy, running on your computer on port 8888. This means you can get it to work in Firefox as well, by changing the Firefox proxy settings. To do so, open Firefox and click Tools Options. On the General tab, click the Connection Settings button. In the Connection Settings dialog that appears, check the Manual proxy configuration radio button, and enter localhost on port 8888 as your proxy. You ll need to change this setting back after you finish with Fiddler, otherwise you may not be able to load any web sites.

APP. E]

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The pr e Ins er t ( > function is similar to the ins er t ( ) function, except that it inserts the new node in front of the current node: templatecclass T> void ListItercT>::preInsert(T t) -C ListNodecT>* p = list.newNode(t,current); if (current == list.first) list.first = previous = p; else previous->next = p; The pr e Ins er t operation can be visualized like this:

int main() { int a[] = {1,3,5,7,9}; int b[] = {4,3,2,1,0}; int dot = inner_product(a,a+4,b,1000); cout << "dot=" << dot << '\n'; } sum=1030

Before:

inplace_merge(p,r,q); // merges the segments [p,r[ and [r,q[; // precondition: the two segments must be contiguous and sorted; // postcondition: the segment [p,r[ is sorted;